Answer by Alex Lop. for Program to print all the bits of one byte union without using bitwise operators

Maybe the point of this task is to use arithmetic operations instead of the bitwise ones?Here is an example:

void printByteBits(unsigned char num){    const static int div[8] = {1, 2, 4, 8, 16, 32, 64, 128};    for (int i = 0; i < sizeof(div)/sizeof(div[0]); i++)    {        printf("Bit %d: %d\n", i, (num / div[i]) % 2);    }}

See the output here: https://godbolt.org/z/xUC663